Answer:
The Probability of success $ (p) = 0.10 $
The Sample size $ (n) = 10 $
Solution:
The probability that more than 2 were caused by violent actions:
$P(x > 2) = 1 – P(x \leq 2)$
$P(x > 2) = 1 – \Sigma_{x=0}^{2} (nCx) * p^x * (1 – p)^{n – x}$
$P(x > 2) = 1 – \Sigma_{x=0}^{2} (10Cx) * 0.10^x * (1 – 0.10)^{10 – x}$
$P(x > 2) = 1 – 0.9298$
$P(x > 2) = 0.0702$
Final Answer:
The probability that more than 2 were caused by violent actions $=0.0702 $
