Karen wants to advertise how many chocolate chips are in each Big Chip cookie at her bakery. She randomly selects a sample of 77 cookies and finds that the number of chocolate chips per cookie in the sample has a mean of 13.4 and a standard deviation of 3.5. What is the 99% confidence interval for the number of chocolate chips per cookie for Big Chip cookies? Enter your answers accurate to one decimal place (because the sample statistics are reported accurate to one decimal place).

Answer:

Given Information from Question:

The Sample Mean $(x\bar)=13.4$

The Sample Standard Deviation $(s)=3.5$

The Sample Size $(n)=77$

The Confidence Interval level $=99%$

The critical value at significance level = 1-0.99 = 0.01, and df = n – 1 = 77-1 = 76, The critical value is:

$t_c = t_{\frac{\alpha}{2}, \text{df}} = t_{0.01/2, 76} = 2.642$

The confidence interval:

$CI = \overline{x} \pm t_c \times \frac{s}{\sqrt{n}} = 13.4 \pm 2.642 \times \frac{3.5}{\sqrt{77}} = (12.3462, 14.4538) $

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