Suppose that the systolic blood pressure of males ( measured in mm ) has a distribution that is approximately normal, with μ = 125 and standard deviation σ = 15. Find the probability that a random male has a blood pressure greater than 137 mm.

Answer:

Given:

The population mean $(𝜇) = 125$

The population standard deviation $(\sigma)=15$

Solution:

The probability that a random male has a blood pressure greater than 137 mm:

$\therefore P(x > 137) = P\left(\frac{x – \mu}{\sigma} > \frac{137 – 125}{15}\right) = P(z > 0.8) = 0.2119$