The mean amount of time it takes a kidney stone to pass is 13 days and the standard deviation is 5 days. Suppose that one individual is randomly chosen. Let X = time to pass the kidney stone. Round all answers to 4 decimal places where possible.

a. What is the distribution of X? X ~ N(,)

b. Find the probability that a randomly selected person with a kidney stone will take longer than 11 days to pass it.

c. Find the minimum number for the upper quarter of the time to pass a kidney stone. (Hint: the number at which 25% takes longer than) days.

Answer:

Given:

The population mean $(μ)=13$

The population standard deviation $(\sigma)=5$

Solution:

(A) The distribution of x : X~N (13,5)

(B) The probability that a randomly selected person with a kidney stone will take longer than 11 days to pass it:

$P(x > 11) = P\left(\frac{x – \mu}{\sigma} > \frac{11 – 13}{5}\right) = P(z > -0.4) = 0.6554$

C) The minimum number for the upper quarter of the time to pass a kidney stone:

→ The z-score for right probability 0.25 = 0.6725

Here we use a z-score formula to find out the x value:

$$z = \frac{x – \mu}{\sigma} \quad $$ $$ \therefore 0.6745 = \frac{x – 13}{5} \quad $$ $$\therefore x = 16 $$

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