The probability that, among twelve of these people, at least 5 have green eyes is ___. (Round to three decimal places as needed.)
Answer:
Given:
Probability of success $(p)=0.60$
Sample size $(n)=12$
Solution:
The probability that among twelve of these people at least 5 have green eyes:
$\text{P}(x \geq 5) = \sum_{5}^{12} \binom{n}{x} \cdot p^x \cdot (1-p)^{n-x} = \sum_{5}^{12} \binom{12}{x} \cdot 0.60^x \cdot (1-0.60)^{12-x} = 0.9427$
Final Answer:
The probability that among twelve of these people at least 5 have green eyes $=0.9427$
