Thirty-nine percent of U.S. adults have very little confidence in newspapers. You randomly select ten U.S. adults. Find the probability that the number who have very little confidence in newspapers is (1) exactly three.
Answer : Given information : Probability of success $(p) = 0.39$ Sample size $(n) = 10$ Solution : → The probability exactly three : $$P(x = 3) = \binom{n}{x} \cdot p^x \cdot (1-p)^{n-x}$$ $$= \binom{10}{3} \cdot 0.39^3 \cdot (1 –…