Out of a sample of 30 people, 12 individuals have diabetes. Compute a 95% confidence interval for the proportion of individuals who have diabetes.

Answer:Given:Favorable Cases $(x)=12$ Sample Size $(n)=30$ Confidence Interval Level $= 95\%$ Solution:The Sample Proportion $(\hat{p}):$$\hat{p} = \frac{12}{30} = 0.4$ The Significance Level $(\alpha):$$\alpha = 1 – 0.95 = 0.05$ The critical value $(z_c):$$z_c = Z_{\alpha/2} = Z_{0.05/2} = 1.96$ The…

Out of a sample of 50 people, 22 individuals have high cholesterol. Compute a 95% confidence interval for the proportion of individuals who have high cholesterol.

Answer:Given:Favorable Cases $(x)=22$ Sample Size $(n)=50$ Confidence Interval Level $= 95\%$ Solution:The Sample Proportion $(\hat{p}):$$\hat{p} = \frac{22}{50} = 0.44$ The Significance Level $(\alpha):$$\alpha = 1 – 0.95 = 0.05$ The critical value $(z_c):$$z_c = Z_{\alpha/2} = Z_{0.05/2} = 1.96$ The…