Answer:
Given:
Probability of success $(p)=0.2 $
Sample size $(n)= 8$
Solution:
The probability that x is less than or equal to 1:
$P(x \leq 1) = \sum_{0}^{1} \binom{n}{x} \cdot p^x \cdot (1-p)^{n-x} = \sum_{0}^{1} \binom{8}{x} \cdot 0.2^x \cdot (1-0.2)^{8-x} = 0.5033$
Final answer:
The probability that x is less than or equal to 1 = 0.5033
