Answer:
The standard deviation $(\sigma):$
$\sigma = \sqrt{n \cdot p(1 – p)} = \sqrt{80 \cdot 0.16(1 – 0.16)} = 3.28$
The probability that an individual is left-handed is 0.16. In a class of 80 students, what is the standard deviation of the number of left-handed students? Round to the nearest hundredth.
